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Kamis, 10 Oktober 2013

Himpunan


Jika P,Q,R adalah himpunan ,buktikan bahwa
(PᴗQ)ᴖ(PcᴖR)c = Pᴗ(QcᴗR)c
Pembuktian
Pembuktian 1
Diketahui :
P={1,3,4,6,7}                      S={1,2,3,4,5,6,7,8,10,11,13}
Q={2,3,4,5,8,10}               
R={1,6,10,11,13}
Jawab :
PᴗQ                       ={1,2,3,4,5,6,7,8,9,10}                    QC                             ={1,6,7,11,13}
PC                                ={1,2,3,4,5,6,7,8}                            QCᴗR                         ={1,6,7,10,11,13}
PCᴖR                     ={10,11,13}                                     (QCᴗR)C                         ={2,3,4,5,8}
(PCᴖR)C                ={1,2,3,4,5,6,7,8}                             

(PᴗQ)ᴖ(PCᴖR)C            ={1,2,3,4,5,6,7,8}                    Pᴗ(QCᴗR)C               ={1,2,3,4,5,6,7,8}


Pembuktian 2
Diketahui :
P={a,b,d,h,i,k}                   S={a,b,c,d,e,f,g,h,i,j,k}
Q={b,c,e,f,h}
R={c,d,g,h,j}
Jawab :
PᴗQ                       ={a,b,c,d,e,f,h,i,k}                             Qc                                    ={a,d,g,i,j,k}      
Pc                                 ={c,f,g,j}                                           QcᴗR                         ={a,c,d,g,h,I,j,k}
PcᴖR                      ={c,g,j}                                             (QcᴗR)c                          ={b,e,f}
(PcᴖR)c                      ={a,b,d,e,f,h,i,k}                                                              
 (PᴗQ)ᴖ(PcᴖR)c    ={a,b,d,e,f,h,i,k}                                   Pᴗ(QcᴗR)c                  ={a,b,d,e,f,h,I,k}

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